Point Slope Form: #(y-y_1) = m(x-x_1)# For a line with slope -3 and point (-2,4), plug -3 in for m, -2 for #x_1#, 4 for #y_1#. Standard Form: Ax + By = C Where A, B, and C are integers. To write an equation in standard form, rewrite the equation in point slope form so that it fits the formula for standard form. #y + 3x = - 2#
Dylan B. 3 Answers By Expert Tutors
Hi Dylan B. You can use the Slope Intercept Form of a line and the coordinates given to develop your line Slope Intercept Form is y = mx + b; where m is the slope You are given m = -2/3 We can start with y = (-2/3)x + b Now use the coordinates given (3,4) to solve for b y = (-2/3)x + b 4 = (-2/3)*3 + b 4 = -2 + b 4 + 2 = b and your line is y = (-2/3)x + 6 I hope this helps
Michelle P. answered • 05/24/21 A pre-student teacher with a passion for math!
I'm going into this problem assuming that your teacher is asking for slope-intercept form (y = mx + b). If it's something else, feel free to correct me. You have two useful pieces of info in this problem:
The only missing component is the y-intercept, b. We can plug in what we know into the general slop-intercept form equation to obtain the y-intercept of the line. So we start with y = mx+b Plug in m = -2/3, x = 3, and y = 4: 4 = (-2/3)(3) + b Now we want to get b by itself. Multiply -2/3 and 3: 4 = -2 + b Add 2 to both sides 6 = b So the line has a y-intercept of 6. Plug our newfound b value and given m value into y=mx+b, and your final answer is: y = (-2/3)x + 6
Use ;point-slope form (y - 4) / (x - 3) = -2/3 |