How many grams of H2O will be produced when you burn 2.5 grams of methane (CH4+2O2 --> CO2 + 2H2O)

#CH_4+2O_2rarrCO_2+2H_2O#

Imole #rarr#2 moles

Convert to grams.

( #A_rC=12,A_rH=1,A_rO=16)#

#[12+(4xx1)]grarr2xx[16+(2xx1)]g#

#16grarr2xx18=36g#

I have assumed the mass of methane to be #5xx10^3g#.

So #1grarr36/16g#

So #5xx10^(3)grarr(36)/(16)xx5xx10^(3)g#

#=11.25xx10^(3)g#

#=11.25kg#